1. 172.10..0.0/19
jawab: 11111111.11111111.11100000.00000000
Jumlah subnet = 2 pangkat x = 2 pangkat 3 karena 1 pada blok subnet 3 ada 3..= 8
Jumlah Host = 2 pangkat y – 2 = 2 pangkat 13 – 2 karena 0 pada sisa blok 3 dan semua blok 4 ada 13 buah = 4096-2=4094
Blok Subnet = 32 karena harga dari angka 1 pada blok 3 adalah 32
Subnet 173.0.0.0 173.0.32.0 173.0.64.0 173.0.96.0
Host 1 173.0.0.1 173.0.32.1 173.0.64.1 173.0.96.1
Host 2 173.0.0.2 173.0.32.2 173.0.64.2 173.0.96.2
Host Terakhir 173.0.31.254 173.0.63.254 173.0.95.254 173.0.127.254
Broadcast 173.0.31.255 173.0.63.255 173.0.95.255 173.0.127.255
Lanjutan
173.0.128.0 173.0.160.0 173.0.0.192.0 173.0.224.0
173.0.128.1 173.0.160.1 173.0.0.192.1 173.0.224.1
173.0.128.2 173.0.160.2 173.0.0.192.2 173.0.224.2
173.0.159.254 173.0.191.254 173.0.223.254 173.0.255.254
173.0.159.255 173.0.191.255 173.0.223.255 173.0.255.255
2. 10.0.0.0/16
Jawab : 11111111.11111111.00000000.00000000
Jumlah subnet = 2 pangkat x = 2 pangkat 8 karena pada subnet blok 2 ada 8 buah 1 = 256
Jumlah host = 2 pangkat y – 2 = 2 pangkat 16 – 2 karena pada sisa blok subnet 3 dan 4 ada 16 buah 0 = 65536 – 2 = 65534
Blok Subnet = 1 (1,2,3….255)
Subnet 10.0.0.0 10.1.0.0 10. … .0.0 10.255.0.0
Host 1 10.0.0.1 10.1.0.1 10. … .0.1 10.255.0.1
Host 2 10.0.0.2 10.1.0.2 10. … .0.2 10.255.0.2
Host Terakhir 10.0.255.254 10.1.255.254 10. … .255.254 10.255.255.254
Broadcast 10.0.255.255 10.1.255.255 10. … .255.255 10.255.255.255
3. 10.0.0.0/24
Jawab = 11111111.11111111.11111111.00000000
jumlah subnet = 2 pangkat x = 2 pangkat 16 karena ada 16 buah 1 pada blo subnet 2 dan 3 = 65536
jumlah host = 2 pangkat y – 2 = 2 pangkat 8 – 2 = 256 – 2 = 254
Blok Subnet = 1
Subnet I = 10.0.0.0
IP Min = 10.0.0.1
IP Maks = 10.0.255.254
IP Broadcast = 10.0.255.255
Subnet II = 10.1.0.0
4. 172.16.0.0/27
Jawab = 11111111.11111111.11111111.11100000
Jumlah Subnet = 2 pangkat x = 2 pangkat 11 karena ada 11 buah 1 pada blok subnet 3 & 4 = 2048
Jumlah host = 2 pangkat y – 2 = 2 pangkat 5 -2 = 32-2 = 30
Blok subnet = 32
Subnet I = 172.16.0.0
IP Min = 172.16.0.1
IP Maks = 172.16.31.254
IP Broadcast = 172.16.31.255
Subnet II = 172.16.32.0
5. 100.0.0.0/13
Jawab = 11111111.11111000.00000000.00000000
Jumlah Subnet = 2 pangkat 5 = 32
Jumalah host = 2 pangkat 19 – 2 = 524288-2 = 524286
Blok Subnet = 8
Subnet I = 100.0.0.0
IP Min = 100.0.0.1
IP Maks = 100.7.255.254
IP Broadcast = 100.7.255.255
Subnet II = 100.8.0.0
6. 192.168.1.0/30
Jawab = 11111111.11111111.11111111.11111100
Jumlah Subnet = 2 pangkat 6 = 64
Jumlah Host = 2 pangkat 2 – 2 = 2
Blok Subnet = 4
Subnet 1 = 192.168.1.0
IP Min = 192.168.1.1
IP Maks = 192.168.1.2
IP Broadcast = 192.168.1.3
Subnet II = 192.168.1.4
7. 160.100.0.0/17
Jawab = 11111111.11111111.10000000.00000000
Jumlah Subnet = 2 pangkat 1 = 2
Jumlah Host = 2 pangkat 15 – 2 = 32768 – 2 = 32766
Blok Subnet = 128
Subnet I = 160.100.0.0
IP Min = 160.100.0.1
IP Maks = 160.100.127.254
IP Broadcast = 160.100.127.255
Subnet II = 160.100.128.0
NOTE :
x = variabel jumlah angka satu ( 1 ) yang dipinjam ( disesuaikan dengan kelas IP )
y = variabel jumlah nol sisa ( 0 )